For the mass on the spring, how is the period of the harmonic motion related to the spring constant, k?
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Mar 17, 2018
Suppose a mass of m is attached to a spring of spring constant K is lying on a horizontal floor,then you pull the mass such that the spring got stretched by x,so restoring force acting on the mass due to the spring is F=-Kx
We can compare this with equation of S.H.M i.e F=-momega^2x
So,we get, K=m omega^2
So, omega =sqrt(K/m)
Hence time period is T=(2pi)/omega =2pi sqrt(m/K)
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