Biology, asked by bzjsjjs, 11 months ago

For the MN-blood group system, the frequencies of M and N alleles are 0.7 and 0.3, respectively. The expected frequency of MN-blood group bearing organisms is likely to be a. 42% b. 49% c. 9% d. 58% solve this question

Answers

Answered by Anonymous
2

Answer:

heya..

here is ur answer

From the equation,

From the equation,(p + q)2 = p2 + 2pq + q2 = 1

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq 

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq = 2 x 0.7 x 0.3 

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq = 2 x 0.7 x 0.3 Thus, expected frequency of MN group = [(2 x 0.7 x 0.3)/1] x 100

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq = 2 x 0.7 x 0.3 Thus, expected frequency of MN group = [(2 x 0.7 x 0.3)/1] x 100= 42%.

i hope its help u

Answered by Anonymous
2

Answer:

From the equation,

From the equation,(p + q)2 = p2 + 2pq + q2 = 1

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq 

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq = 2 x 0.7 x 0.3 

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq = 2 x 0.7 x 0.3 Thus, expected frequency of MN group = [(2 x 0.7 x 0.3)/1] x 100

From the equation,(p + q)2 = p2 + 2pq + q2 = 1MN = 2pq = 2 x 0.7 x 0.3 Thus, expected frequency of MN group = [(2 x 0.7 x 0.3)/1] x 100= 42%.

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