Physics, asked by serenesmile9843, 1 year ago

For the network shown in the figure the value of the current i is(a) \frac{9V}{35}(b) \frac{18V}{5}(c) \frac{5V}{9}(d) \frac{5V}{18}

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Answered by ROCKSTARgirl
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Answered by Anonymous
0

Hello Friend

The answer of u r question is

Option.D

Thank you

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