Question

For the one dimensional motion of a particle, described by position X = t + cost , the velocity of a particle is zero at time t equals to
(a) 0.3 s
(b) 1 s
(c) 0.2 s
(d) 1.57 s

Answer 1

Answer:

d

Explanation:

because where dx/dt zero velocity zero

Answer 2

Answer:

(d) 1.57 s

Explanation:

Given that

X = t + cos t

We know that velocity of particle given as

$V=\dfrac{dX}{dt}$

X = t + cos t

$\dfrac{dX}{dt}=1-sin t$

So

V=1-sin t

We have to find time when velocity of particle is zero(V=0)

V=1-sin t = 0

1 = sin t

$t=sin^{-1}1$

t= 90 °=π/ 2

We know that

π = 3.14

t= 3.14/ 2  = 1.57 s

At t= 1.57 s the velocity of particle will be zero.

(d) 1.57 s