For the one-dimensional motion of a particle, described by position x = t+cost (where t is time in s and x is in m), the velocity of particle is zero at time t equal to
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4From the figure ,
We know simple harmonic motion satisfied condition.
a = -w²x
Where A , w is positive constant
(A) at t = 0.3
X is negative
Slope of graph at t = 0.3 negative so, velocity < 0 .
a will be positive because displacement is negative { a=-w²x}
(B) at t = 1.2
X is positive { shown in figure }
slope of displacement - time graph is positive at t = 1.2 so, velocity will be positive .
acceleration will be negative because displacement is positive .
(C) at t = -1.2
Displacement is negative.
Slope of graph at t= -1.2 is positive so, velocity at t = -1.2 is positive .
Acceleration will be positive because displacement is negative.
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