Physics, asked by ashermitul5, 1 year ago

For the path PQR in a conservative force field the amounts work done in carrying a body from P to Q and from Q to R are 5 Joule and 2 Joule respectively. The work done in carrying the body from P to R will be-
a) 7 J
b) 3 J
c)√21 J
d) zero


ashermitul5: plz explain your answer
ashermitul5: give me a full solution of this plzz

Answers

Answered by kokan6515
74
Conservative forces r those which do not depends on the path chosen.
so work done be same in both cases that is 7 joules
Answered by puja49kumari
76

Explanation:

work done in closed path in a conservative field is zero.

W(P to Q)+W(Q to R)+W(R to P)=0

2 +5+W(R to P)=0

7 +W (R to P)=0

W (R to P)=-7

-W (P to R)=-7

W (P to R )=7 j

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