Question

For the peoduction of x rays of waveleagth 0.1a the minimum potential difference will be

Answer 1

) none of these. Q.15.For the production of x -rays of wavelength 0.1 A, the minimum potential difference will be. (a) 12.4 KV

Answer 2

Explanation:

It is given that,

Wavelength of x - rays, $\lambda=0.1\ A=0.1\times 10^{-10}\ m$

We have to find the minimum potential difference. the relationship between the wavelength and the potential difference is given by :

$\lambda=\dfrac{h}{\sqrt{2me} }\dfrac{1}{\sqrt{V} }$

Where

$\dfrac{h}{\sqrt{2me} }=constant$

So, $\lambda=\dfrac{12.27}{\sqrt{V} }\ A$

$V=\dfrac{12.27^2}{\lambda^2}$

$V=\dfrac{12.27^2}{(0.1\times 10^{-10}\ m)^2}$

$V=1.5\times 10^{24}\ Volts$

Hence, this is the required solution.