For the period 1960-1983, the metre was defined to be 1,650, 763 73 wavelengths of a certain orange red light emitted by atoms. Compute the distance of the wavelength in nanometres to the correct number of significant figures.
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Answer:
The energy of a photon is given by E=hf, where h is the Planck constant and f is the frequency. The wavelength λ is related to the frequency by λf=c, so E=hc/λ.
Since,
h=6.626×10
−34
J⋅s and c=2.998×10
8
m/s
hc=
(1.602×10
−19
J/eV)(10
−9
m/nm)
(6.626×10
−34
J⋅s)(2.998×10
8
m/s)
=1240eV⋅nm
Thus,
E=
λ
1240eV⋅nm
With
λ=(1,650,763.73)
−1
m=6.0578021×10
−7
m=605.78021nm
we find the energy to be
E=
λ
hc
=
605.78021nm
1240eV⋅nm
=2.047eV
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