Question

for the plymanial p(x)-(x2-2) find a zcro​

Answer 1

Answer:

P(x)=(x−2)

2

−(x−2)

2

This is in the form of a

2

−b

2

P(x)=(x−2+x+2)(x−2−(x+2))

P(x)=2x(x−2−x−2)

P(x)=2x(−4)

P(x)=0

−8x=0

x=0

Hence,

x=0 is the zero of the polynomial P(x)

Answer 2

*Answer:*

x = √2

Step-by-step explanation:

if p(x)= x² - 2

x² = 2

x = √2