for the polynomial p(x) 1/2x^2 -3x+2 find the difference of zeroes
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Sol:
α and β are the zeroes of the polynomial f(x) = 2x² + 5x + k.
Sum of the zeroes = α + β = -(coefficient of x) / (coefficient of x2) = -5/2.
Product of the zeroes = αβ = -(constant term) / (coefficient of x2) = k/2.
α²+β²+αβ = 21/4
⇒ (α + β)2 - αβ = 21/4
⇒ (-5/2)2 - k/2 = 21/4
⇒ 25/4 - k/2 = 21/4
⇒ k/2 = 25/4 - 21/4
⇒ k/2 = 1
⇒ k = 2
α and β are the zeroes of the polynomial f(x) = 2x² + 5x + k.
Sum of the zeroes = α + β = -(coefficient of x) / (coefficient of x2) = -5/2.
Product of the zeroes = αβ = -(constant term) / (coefficient of x2) = k/2.
α²+β²+αβ = 21/4
⇒ (α + β)2 - αβ = 21/4
⇒ (-5/2)2 - k/2 = 21/4
⇒ 25/4 - k/2 = 21/4
⇒ k/2 = 25/4 - 21/4
⇒ k/2 = 1
⇒ k = 2
Anonymous:
sry u read it wrongly
Answered by
5
here is the answer in graph.
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