Question

For the polynomial p(x) = x² - x – 2 find the values of p(0), p(1) and p(-1)?​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

$\huge\red{\underline{ \underline{Answer :}}}$

$p(x) = {x}^{2} - x - 2$

$Just \: \: substitute \: \: these \: \: values \: \: in \: \: x .$

$p(0) = {(0)}^{2} - (0) - 2$

$\: \: \: \: \: \: \: \: \: \: = 0 - 0 - 2$

$\: \: \: \: \: \: \: \: \: \: = - 2$

$\bold{ \large{ \boxed{p(0) = - 2}}}$

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$p(1) = {( 1)}^{2} - (1) - 2$

$\: \: \: \: \: \: \: \: \: \: = 1 - 1 - 2$

$\: \: \: \: \: \: \: \: \: \: = 0 - 2$

$\: \: \: \: \: \: \: \: \: \: = - 2$

$\bold{ \large{ \boxed{p(1) = - 2}}}$

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$p( - 1) = {( - 1)}^{2} - ( - 1) - 2$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 + 1 - 2$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 - 2$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0$

$\bold{ \large{ \boxed{p( - 1) = 0}}}$

$\purple{ \bf{ \tt{Hope \: \: this \: \: helps \: \: you \: !}}}$