Question

For the polynomial p(x) = x² - x – 2 find the values of p(0), p(1) and p(-1)? ​

Answer 1

Step-by-step explanation:

p(x) = x²-x-1. p(0) = (0)²-(0)-1. = -1. p(1) = (1)²-(1)-1. = 1-1-1. = 1-2. = -1 ... find the value of the polynomial x=2 · You want ...

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Answer 2

Answer:

p(0) = -2, p(1) = -2, p(-1) = 0

Step-by-step explanation:

we have to find the values of p(0), p(1) and p(-1) for the polynomial p(x) = x square -x-2

for x=0,p(0) = 0 square -0-2 = 0-0-2 = -2

for x = 1, p(1)= 1 square -1-2 = 1-1-2 = -2

for x = -1,p(-1)= -1 square-(-1)-2 = 1+1-2 = 0