Question

For the polynomial p (y) = y3 - 2y + 8, find p (0), p (1) and p (-2)

Answer 1

Answer:

P(0) = o3-2y+8=8-2y

P(1) = (1) 3-2y+8=11-2y

P(2) = (2)3-2y+8=14-2y

Answer 2

Answer:

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