For the polynomial t2 – 7t + 12, the product of zeroes is
(a) -7 (b) 9 (c) –9 (d) 12
Answers
Answered by
4
Solution:
Given Quadratic polynomial : t² - 7t + 12
here,
- a = 1
- b = -7
- c = 12
Product of zeroes = c/a
Product of zeroes = 12/1
Product of zeroes = 12
Verification :
Let α and β are the zeroes of Quadratic polynomial t² - 7t + 12
›› t² - 4t - 3t + 12
›› t(t - 4) - 3(t - 4)
›› (t - 3)(t - 4)
›› t = 3 or x = 4
Product product of zeroes = αβ
αβ = 12
3 × 4 = 12
12 = 12
LHS = RHS
Hence Verified
- Option d) is correct ✓
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Answered by
1
alpha*beta = C*A
C=12
A=1
12*1=12
so product of zero is 12
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