Math, asked by archikumari9, 8 months ago

For the polynomial t2 – 7t + 12, the product of zeroes is

(a) -7 (b) 9 (c) –9 (d) 12​

Answers

Answered by llSecreTStarll
4

Solution:

Given Quadratic polynomial : t² - 7t + 12

here,

  • a = 1
  • b = -7
  • c = 12

Product of zeroes = c/a

Product of zeroes = 12/1

Product of zeroes = 12

Verification :

Let α and β are the zeroes of Quadratic polynomial t² - 7t + 12

›› t² - 4t - 3t + 12

›› t(t - 4) - 3(t - 4)

›› (t - 3)(t - 4)

›› t = 3 or x = 4

Product product of zeroes = αβ

αβ = 12

3 × 4 = 12

12 = 12

LHS = RHS

Hence Verified

  • Option d) is correct

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Answered by gauravsharma27142
1

alpha*beta = C*A

C=12

A=1

12*1=12

so product of zero is 12

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