Question

For the projectile motion given by y = 80x - 4x^2. Range is given by (in m) : ( Note : Ata ho to hi krna faltu answer mt likhna)​

Answer 1

Answer:

see the attachment for the answer

Answer 2

RANGE IS 20 METRES.

Given:

• y = 80x - 4x²

To find:

• Rangle of projectile ?

Calculation:

Range of a projectile is the X axis displacement of the 2D motion (i.e. projectile)

Now, for range, the body starts from ground and ends at ground, such that Y displacement should be zero.

Putting value of y = 0

$y = 80x - 4 {x}^{2}$

$\implies \: 0 = 80x -4 {x}^{2}$

$\implies \: 4 {x}^{2} = 80x$

$\implies \: 4 x = 80$

$\implies \: x = 20 \: m$

So, range of projectile is 20 metres.