Question

for the quadratic eq 3+14t-5t2 the sum of zeroes will be?​

Answer 1

Answer⤵️⤵️

The first term is, 5t2 its coefficient is 5 .

The middle term is, +14t its coefficient is 14 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 5 • -3 = -15

Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is 14 .

-15 + 1 = -14

-5 + 3 = -2

-3 + 5 = 2

-1 + 15 = 14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 15

5t2 - 1t + 15t - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

t • (5t-1)

Add up the last 2 terms, pulling out common factors :

3 • (5t-1)

Step-5 : Add up the four terms of step 4 :

(t+3) • (5t-1)

Which is the desired factorization