for the quadratic eq 3+14t-5t2 the sum of zeroes will be?
Answers
Answer⤵️⤵️
The first term is, 5t2 its coefficient is 5 .
The middle term is, +14t its coefficient is 14 .
The last term, "the constant", is -3
Step-1 : Multiply the coefficient of the first term by the constant 5 • -3 = -15
Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is 14 .
-15 + 1 = -14
-5 + 3 = -2
-3 + 5 = 2
-1 + 15 = 14 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 15
5t2 - 1t + 15t - 3
Step-4 : Add up the first 2 terms, pulling out like factors :
t • (5t-1)
Add up the last 2 terms, pulling out common factors :
3 • (5t-1)
Step-5 : Add up the four terms of step 4 :
(t+3) • (5t-1)
Which is the desired factorization