Math, asked by ranjaykumargmo1486, 6 months ago

For the quadratic equation 6x2=7x-1, find the values of a , b ,c

Answers

Answered by Anonymous
17

Answer:

 {\bold{ \underline{{given \: quadratic \: equation}}}}

6x²= 7x-1

6x²-7x+1=0

Comparing the given quadratic equation with ax²+bx+c = 0

a= 6

b= -7

c= 1

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Answered by akshay0222
0

Given,

The given quadratic equation\[ = 6{x^2} - 7x + 1.\]

Solution,

Know that a quadratic equation is defined as \[a{x^2} + bx + c = 0\].

Comparing the given equation with the standard equation.

Therefore,

\[\begin{array}{l} \Rightarrow a = 6\\ \Rightarrow b =  - 7\\ \Rightarrow c = 1\end{array}\]

Hence, the value of a,b and c is \[6, - 7{\rm{and1}}{\rm{.}}\]

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