Math, asked by Anonymous, 9 months ago

For the quadratic equation x^2 - 2x +1 = 0 find the value of x+1/x​

Answers

Answered by AJAYMAHICH
7

Step-by-step explanation:

x^2-2x+1 = 0

x^2 - x -x +1 = 0

x(x-1)-1(x-1) = 0

(x-1)(x-1) = 0

x = 1,1

x+1/x = 1+(1/1) = 1+1 = 2

Answered by Anonymous
0
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.........

x^2-2x+1 = 0

x^2 - x -x +1 = 0

x(x-1)-1(x-1) = 0

(x-1)(x-1) = 0

x = 1,1

x+1/x = 1+(1/1) = 1+1 = 2

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