Question

for the quadratic equation x 2 x -5 =0 find the value b^2 - 4ac

Answer 1

Answer:

$d(discriminant) = {b}^{2} - 4ac \\ a = 1 \\ b = 1 \\ c = - 5 \\ = ( {1}^{2} ) - 4 \times 1 \times ( - 5) \\ = 1 - 4 \times ( - 5) \\ = 1 - 20 = - 19$

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Answer 2

Answer:

–x–=+

-4×-5=+20

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