Question

for the quadratic eqution 2x^2-5x+2=0 the value of discriminant (1) 9 (2)-41 (3) 13 (4) 41​

Answer 1

Option (4) 41.

Given :-

• Quadratic equation ; 2x² - 5x + 2 = 0

To Find :-

• The value of discriminant.

Solution :-

Given, 2x² - 5x + 2 = 0,

On comparing with ax² + bx + c = 0 , We get ;

↪ a = 2 , b = -5 , c = 2

Now, we need to find the value of discriminant.

⭐ Discriminant = b² - 4ac

[ Putting values ]

↪ D = (-5)² - 4(2)(-2)

↪ D = 25 - 8 × -2

↪ D = 25 + 16

↪ D = 41

Hence,

• The value of discriminant is 41.

Answer 2

Answer:

$\sf\bold{Question:}$

For the quadratic eqution 2x²-5x+2=0 the value of discriminant (1) 9 (2) -41 (3) 13 (4) 41

$\bold{\underline{Given:-}}Quadratic\: eq.\: 2x²-5x+2=0$

$\bold{\underline{To~find:-}} Value\: of\: discriminant$

$\bold{\underline{Solution:-}} Comparing~ the~ eq ~with ~ax²+bx+c =0 \\ \\ a= 2 \: \: \: b=5 \: \:\: c=2 \\ \\ <strong>Discriminant </strong><strong>=</strong><strong> </strong><strong>b²</strong><strong>-</strong><strong>4</strong><strong>a</strong><strong>c</strong><strong> </strong><strong> </strong>\\ \\ Putting~the~values : \\ \\ D = (-5)²-4(2)(-2) \\ \\ \implies D= 25 +16 \\ \\ \implies <strong>D=</strong><strong> </strong><strong>4</strong><strong>1</strong><strong> </strong>$

$\sf\red{Hence,~ the ~correct ~opt. ~is ~ 42}$