Question

For the reaction 1/2 N2(g) +3/2 H2(g) →NH3(g); H = -30 KJ to be at equilibrium at 477°C. If standard entropy of N2(g) and NH3(g) are 60 and 50 J mol K respectively then calculate the standard entropy of H2) in J Mol K​

Answer 1

Answer:

/2 N2(g) +3/2 H2(g) →NH3(g); H = -30 KJ to be at equilibrium at 477°C. If standard entropy of N2(g) and NH3(g) are 60 and 50 J mol K respectively then calculate the standard entropy of H2) in J Mol K/2 N2(g) +3/2 H2(g) →NH3(g); H = -30 KJ to be at equilibrium at 477°C. If standard entropy of N2(g) and NH3(g) are 60 and 50 J mol K respectively then calculate the standard entropy of H2) in J Mol K