Question

for the reaction 1/8 S8(s) + 3/2 O2(g) =SO2 (g) the difference of heat change at constant pressure & constant volume at 27°C will be
answer in calories​

Answer 1

Answer:

The difference of heat change at constant pressure is ∆H

The difference of heat change at constant volume is∆U...

we know that,

∆H-∆U=nR∆T

In the reaction,

1/8S8(s)+3/2O2(g)—>SO2(g)

∆ngas=1-3/2

∆ngas=-1/2

difference,∆H-∆U=-1/2×R×(300)

∆H-∆U=-150R

Explanation:

Hope it helps you frnd......