Question

for the reaction 1/8 S8(s) + 3/2 O2(g) =SO2 (g) the difference of heat change at constant pressure & constant volume at 27°C will be

Answer 1

Given: The reaction 1/8 S8(s) + 3/2 O2(g) =SO2 (g)

To find: The difference of heat change at constant pressure & constant volume at 27°C ?

Solution:

• Now let the difference of heat change at constant pressure be ∆H and the difference of heat change at constant volume is ∆U.

• We know the formula:

               ∆H - ∆U = nR∆T

• From reaction, we get n = (1 - 3/2) = -1/2

               ∆H - ∆U = nR∆T

               ∆H - ∆U = (-1/2) R (273+27)

               ∆H - ∆U = (-1/2) R (300)

               ∆H - ∆U = -150 R

Answer:

             So the difference of heat change at constant pressure & constant volume at 27°C is -150 R.

Answer 2

Answer:

-150 R

Please refer to the enclosure for the solution

Hope this will be helpful..