Question

For the reaction,
2 NOBr(9) ► 2 NO2(g) + Br_(9),
the rate law is rate = k[NOBr]?. If the rate
of the reaction is 6.5 x 10-6 mol L sl when
the concentration of NOBr is 2 x 10-3 mol
L'. What would be the rate constant for the
reaction?​

Answer 1

Answer:

k = 3.25×10*-3

As, order of this reaction is 1

k= rate/conc.