Question

for the reaction 250, (g) + O2 (g)
toz (g) ~ 2303 (g),
kp = 3x1024 at 250 G
find the value of ke-​

Answer 1

Answer:

Correct option is

A

10 atm

−1

For the reaction,

2SO

2

(g)+O

2

(g)⇌2SO

3

(g)

Given that, ΔG

o

=−690.9R,T=300K

From the formula, ΔG

o

=−RTlnK

−690.9R=−R×300×InK

or lnk=

300

690.9

=2.303

or =2303logK=2303

or K=10

1

=10

Unit of K=(atm)

Δn

=(atm)

2−3

=(atm)

−1

∴K=10atm

−1