Chemistry, asked by anshulsuryavanshi878, 5 months ago

For the reaction 2A + 3B
Products, A is in excess and on chan-
ging the concentration of B from 0.1
M to 0.4 M, rate becomes doubled,
Thus, rate law is
dx = K[A]? [B]?
dt

Answers

Answered by Anonymous

Answer:

Hmm

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Answered by Anonymous

Answer:

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For the reaction 2A + 3BProducts, A is in excess and on chan-ging the concentration of B from 0.1M to 0.4 M, rate becomes doubled,Thus, rate law isdx = K[A]? [B]?dt​

Answers

For the reaction 2A + 3B
Products, A is in excess and on chan-
ging the concentration of B from 0.1
M to 0.4 M, rate becomes doubled,
Thus, rate law is
dx = K[A]? [B]?
dt