Question

For the reaction 2A + B P + 2Q, the rate law is,
r = k[A] [B]. The overall order of the reaction is
(1) 1
(2) 2
(3) 3
(4) 4​

Answer 1

Answer:

For a reaction, A+B→P

R

1

=k[A][B]

2

---------(i)

If the concentration of B is doubled,

R

2

=k[A][2B]

2

---------(ii)

On dividing (i) and (ii)

R

2

R

1

=

k[A][2B]

2

k[A][B]

2

R

2

R

1

=

4B

2

B

2

R

2

=4R

1

The rate of reaction will be four times the initial rate.