Question

For the reaction:2ag+ + zn 2ag + zn2+eocell = 1.56 v. What is the corresponding value of go?

Answer 1

Given:

$2Ag^{+} + Zn-- > 2Ag+Zn^{2+}$

$E^{o} =1.56V$

To find: the value of $G^{o}$.

Formula to be used: $G^{o} =-nFE^{o}$.

Step-by-step method:

Step 1 of 1

The Gibb's free energy can be calculated by multiplying the faraday's constant and the standard cell potential.

The number of moles of electrons transferred in the reaction  $2Ag^{+} + Zn-- > 2Ag+Zn^{2+}$ are 2.

So now we can substitute the values as:

$G^{o} =-2*96485*1.56\\\\G^{o} =-301033.2J\\\\G^{o} =-301.033kJ$

The value of $G^{o}$ is -301.033 kJ.