For the reaction, 2Cl(g) → Cl2 (g), the correct option is : (1) ∆rH > 0 and ∆rS > 0 (2) ∆rH > 0 and ∆rS < 0 (3) ∆rH < 0 and ∆rS > 0 (4) ∆rH < 0 and ∆rS < 0
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2Cl(g)→Cl
2
(g)
Atoms forming a molecule, making system less disordered. Entropy is decreasing ΔS(−ve) in the reaction. Further the addition reaction is exothermic since a bond is being formed, therefore ΔH is also −ve.
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