Question

For the reaction : 2H1 (g)⇌H2(g) + I2(g); the
degree of dissociation (α) of HI(g) is related to
equilibrium constant Kp by the expression -​

Answer 1

Explanation:

For the given reaction, if a is the initial moles of HI and α is the degree of dissociation, 2HI(g)⇌H

2

(g)+I

2

(g)

a(1−2α)αα

K

p

=

p

H

I

2

p

H

2

×p

I

2

Now, p

a

=

n

total

p

total

×n

a

, K

p

=

n

HI

2

n

H

2

×n

I

2

,

K

p

=

(1−2α)

2

α

2

On rearranging, we get, K

p

=

1+2

K

p

2

K

p

.