Question

For the reaction 2N2H4(l) + N204(l) ► 3N2 (g) + 4H20 (l), What is the limiting reagent for this reaction, when two moles of each reactant involve in the reaction: A. N204 B. H2O C. N₂ D. N2H4 ​

Answer 1

Answer:

N2H4.

Explanation:

In the reaction, 2 moles of N2H4 and 1 mol of N2O4 is consumed to produce 3 moles of N2 and 4 moles of H2O. As a result N2H4 gets fully consumed and 1 mol N2O4 remains. Hence, N2H4 is the limiting reagent.