Question

For the reaction; 2n2o5 4no2 + o2 rate and rate constant are 1.02 104 and 3.4 105 sec1 respectively, then concentration of n2o5 at that time will be

Answer 1

Explanation:

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Answer 2

Concentration of $N_2O_5$ at that time will be 0.03 M

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2N_2O_5\rightarrow 4NO_2+O_2$

As units of rate constant is $sec^{-1}$, the order of reaction is first order.

$rate =k[N_2O_5]^1$

Given : rate = $1.02\times 10^4$

rate constant = k = $3.4\times 10^5$

$1.02\times 10^4=3.4\times 10^5\times [N_2O_5]^1$

$[N_2O_5]=0.03M$

The concentration of $N_2O_5$ at that time will be 0.03 M

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