for the reaction: 2n2o5(g) = 4no2(g) + o2(g), it is found that n2o5 is decomposing at the rate of 0.02mol/liter sec. calculate to rate of reaction defined as delta [NO2]/delta t with delta t in second.
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Answer:
0.04
Explanation:
for rate of reaction rate of disappearance of N2O5/2 = rate of appearance of NO2/4
so N2O5/2 =NO2/4
0.02/2 = NO2/4
=0.04mol/lit/sec
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