Question

For the reaction,
2N2O5--->4NO2+O2
Select the correct statement
1) Rate of formation of O2 is same as rate of formation of NO2
2) Rate of disappearance of N2O5 is two times rate of formation of NO2
3)Rate of formation of O2 is 0.5 times rate of disappearence of N2O5
4)Rate of formation of NO2 is equal to rate of disappearence of N2O5

Answer 1

Answer:

Option 2 is the correct one.

Answer 2

Answer:

Option (2) is correct.

Explanation:

Since we have given the reaction as

$2N_{2}O_{5}\rightarrow 4NO_{2}+O_{2}$

We know how to write the rate of reaction for the given reaction,

So,the rate of reaction is represented by

$\dfrac{-dN_{2}O_{5}}{2dt}=\dfrac{+dNO_{2}}{4dt} =\dfrac{+dO_{2}}{dt}$

Where negative sign represent the rate of disappearance while positive sign represents the rate of appearance.

$\dfrac{-dN_{2}O_{5}}{2dt}=\dfrac{+dNO_{2}}{4dt}$

So,

$\dfrac{-2dN_{2}O_{5}}{dt}=\dfrac{+dNO_{2}}{dt}$

So,Option (2) Rate of disappearance of N2O5 is two times rate of formation of NO2 is correct.