Chemistry, asked by nehaliganvit3, 4 months ago

For the reaction 2NOBr(g) <-> 2NO(s) + Br2(g), the equilibrium concentrations are: [NOBr] = 0.46 M, [NO] = 0.1 M, [Br2] = 0.3 M. What will be the value of Kc. *
• 0.065
• 0.0065
• 0.75
• 1

Answers

Answered by abhijithmathew56

Explanation:

For the reaction 2NOBr(g) <-> 2NO(s) + Br2(g), the equilibrium concentrations are: [NOBr] = 0.46 M, [NO] = 0.1 M, [Br2] = 0.3 M. What will be the value of Kc. *

• 0.065

• 0.0065

• 0.75

• 1

answer:

Previous Question

Next Question

Similar questions

English, 2 months ago

For the cultural progremme we have invited a. to tribal dancer...

Science, 2 months ago

Which plant height is dominant?recessive...

Math, 2 months ago

add the following numbers expression a + b -3 , b - a + 3 , a - b + 3...

Chemistry, 4 months ago

(a)write two ores of Aluminum. (b) Define calcination ...

English, 4 months ago

why is refrence to Cupid significant in this context ?

Math, 10 months ago

Find the value of log3√2(324)...

Science, 10 months ago

Why shearing is done before winter ?

Math, 10 months ago

2. State true or false: (1) Every natural number is an integer. (ii) Every integer is a whole number (iii) When two positive integers are added we negative integer (iv) 5-(-5) = 0 (v) O is the smallest integer. (vi) There does not exist the greatest integer (vii) -7 is smaller than 5. (viii) | -97 > 6 (i) 5+(-3) -(-8) is positive. (r) (-10) + (-3) +4>0. (xi) -1, 0, 1 are in ascending order.

For the reaction 2NOBr(g) <-> 2NO(s) + Br2(g), the equilibrium concentrations are: [NOBr] = 0.46 M, [NO] = 0.1 M, [Br2] = 0.3 M. What will be the value of Kc. *• 0.065• 0.0065• 0.75• 1​

Answers

For the reaction 2NOBr(g) <-> 2NO(s) + Br2(g), the equilibrium concentrations are: [NOBr] = 0.46 M, [NO] = 0.1 M, [Br2] = 0.3 M. What will be the value of Kc. *
• 0.065
• 0.0065
• 0.75
• 1