Question

for the reaction 2So2 + o2 ----> 2So3 the rate of disapperance of o2 is 2.0 * 10 power -4 mol-1 s-1. the rate of appearance of so3 is​

Answer 1

4×10-⁴mol-¹s-¹

Explanation:

Reaction: $\bf{2}$SO$\small{2}$ + O$\small{2}$ —> $\bf{2}$SO$\small{3}$

By differential rate law:

Rate= R.O.D of O$\small{2}$ = R.O.A of SO$\small{3}$

$\dfrac{–[O \small{2}]}{dt}$ = $\dfrac{+1}{2}$ $\dfrac{[SO \small{3}]}{dt}$

Given: Rate of Disappearance of O$\small{2}$ = 2×10-⁴mol-¹s-¹

2(2 × 10-⁴)= $\dfrac{[SO \small{3}]}{dt}$

4 × 10-⁴ = $\bf{x}$

$\sf\boxed{Hence\: Rate\:of\: Appearance=4×10-⁴}$

Hope it helps you ^_^