Question

For the reaction 4 A + 5 B → 2 C + 3 D, what is the magnitude of the rate of change for [B] when [A] is decreasing at 0.930 M/s?

Answer 1

Answer:

1.16 is right answer.

Explanation:

Refer attachment!!!

Answer 2

Given:

For the reaction 4 A + 5 B → 2 C + 3 D, [A] is decreasing at 0.930 M/s.

To find:

We have to find the rate of change of [B].

Solution:

The given reaction is-

4 A + 5 B → 2 C + 3 D

The rate of the reaction is given as-

$\dfrac{-[A]}{4dt}=\dfrac{-[B]}{5dt}=\dfrac{[C]}{2dt}=\dfrac{[D]}{3dt}$.

Hence we can write-

$\dfrac{-[A]}{4dt}=\dfrac{-[B]}{5dt}$

Given that the rate of decrease of [A] is 0.930M/s.

Thus $\dfrac{-[A]}{dt}=0.93$

Let the rate of change for [B] be x.

So, we can write-

$\frac{0.93}{4} = \frac{x}{5} \\ x = 1.1625$

The value of x is 1.1625.

Thus, the rate of change of [B] is 1.1625M/s.