Question

For the reaction A + 2B = C. 5 mole of A and 8 mole of B will produce

Answer 1

A + 2B --------> C
multiply it with 4,
4A + 8B --------> 4C
since all the 8 moles of B have reacted...1 mole of A will be left unreacted.
Hence 4 moles of C are formed!!

Answer 2

Answer: The moles of C produced are 4 moles.

Explanation:

For the given chemical reaction:

$A+2B\rightarrow C$

By Stoichiometry of the reaction:

2 moles of B reacts with 1 mole of A.

So, 8 moles of B will react with = $\frac{1}{2}\times 8=4$ moles of A.

The given amount of A is more than the required amount. Thus, A is present in excess and is considered as an excess reagent.

B is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of B produces 1 mole of C.

So, 8 moles of B will produce = $\frac{1}{2}\times 8=4$ moles of C.

Thus, the moles of C produced are 4 moles.