Question

For the reaction A + 2B REVERSIBLE C the expression for equilibrium constant is​

Answer 1

Answer:

Given reaction :

A + 2B <-------> C

Let the vol. of the sol. = V

We know,

Equilibrium Constant, Kc = [product]^x /[Reactant]^y

Now, Kc for the given reaction is = [C]/([A] × [B]^2) = C/V/{A/V×(B/V)^2}

CV^3/VAB^2 = CV^2/AB^2

Hence, Kc = CV^2/AB^2