Question

For the reaction A + 3B 2C + D, initial mole of A is twice that of B. If at equilibrium moles of B and C
are equal, then percent of B reacted is
(2) 20%
(3) 40%
(4) 60%
(1) 10%​

Answer 1

Answer:

the ans is 60%

Explanation:

here,

c has 2 moles and B has 3

so total moles=3+2=5

now,

$b = \frac{3}{5} \times 100\% = 60\%$