Question

For the reaction a + 3b is in equilibrium with 2c+d initial mole of a is twice that of b if at equilibrium of b and c are equal thenpercent of b reacted

Answer 1

Here according the equation, 1 mole of A will combine with 3 mole of B and so if x mole of A is consumed then it will combine with 3x mole of B and similarly we can calculate the number of mole of C and D formed(according to their stoichiometric coefficient: just think about this stoichiometry : its very basic and important!!!!)

Now from the question given that, at equilibrium,

(a/2)-3x = 2x

a/2= 5x,

x=a/10

so amount of B reacted=3x=3a/10

Initial amount of B=a/2

so % of B reacted= {3a/10}/{a/2} *100

=6/10 *100=60%