Question

For the reaction A +B --------- C + D doubling the concentration of both the reactants increases the reaction rate by 8 times and doubling the concentration of only B simply doubles the reaction rate. Find the rate law for the equation.

Answer 1

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Answer 2

Answer: The rate law for the equation is written as :

$R=k[A]^2[B]^1$

Explanation:

$A+B\rightarrow C+D$

Let the rate law be written as $R=k[A]^x[B]^y$...(1)

Doubling the concentration of both the reactants increases the reaction rate by 8 times,So,:

$8R=k[2A]^x[2B]^y$...(2)

Doubling the concentration of only B simply doubles the reaction rate, the reaction rate expression will be written as :

$2R=k[A]^x[2B]^y=R\times 2^y$,we get$y=1$

On dividing (1)and (2) we get:

$2^x\times 2^y=8$

Now on putting value ,y=1, we get:

$x=2$

So, the rate law for the equation is written as :

$R=k[A]^2[B]^1$