Question

For the reaction, A(g) + 2 B(g) 4 C(g) + 3 D(g) When 0.5 mole of A and 1 mole of B are allowed to react then​

Answer 1

Answer:

"In a reaction, A+2B→2C, in starting the 3.0 mole of 'B' and 2.0 of mole 'C' are placed in a 2.0L flask and the equilibrium concentration of 'C' is 0.5 mol/L. The equilibrium constant (K) for the reaction is

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Answer

Correct option is

C

0.05

A+2B→2C

Let t = 0 (Initially) 2 3 2

t = t 2 - x 3 - 2x 2x + 2

x = -0.5

(Initially Now, [C] = 0.5 mol/L = (2x + 2)/2 mol/L

Put x = - 0.5 at time t

Thus, A = 2.5

B = 4

C = 1

K=(C)

2

/(A)(B)

2

K=(1/2)

2

/(2.5/2).(4/2)

2

[Dividing moles by 2 {volume given} as we express here in terms of concentration

K = 1/20

K = 0.05