Question

For the reaction
A(g) + 2B(g) → 2C(g) + 3D(g)
the change of enthalpy at 27°C is 19 kcal. The value of ∆E is
(a) 21.2 kcal (b) 17.8 kcal
(c) 18.4 kcal (d) 20.6 kcal

Answer 1

Answer:

the answer is the a is a answer

Answer 2

Answer:

(b) 17.8 kcal

Explanation:

∆ H = 19 kcal = 19 × 10^3 cal

n = 2 mole

T = 27°C = 300 K

R = 2 cal

∆ E = ∆H - ∆n RT

=19× 10^3 - (2×2×300)

∆E =17.8 kcal

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