For the reaction a(g)+ b(g)=c(g)+d(g) occurring in a closed vessel of 1L volume the value of equilibrium constant is 16 at a particular temperature if the number of moles of each of the constituents be 1 then also calculate the molar concentration of b(g) and d(g)
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Option D is correct
A2+B2→C2+D2
At t=0 1 1 1 1
t=eq 1-x 1-x 1+x 1+x
KC=[1−x]2[1+x]2
Given KC=0.25 so
0.25=[1−x]2[1+x]2
0.25=1−2x+x21+2x+x2
0.25−0.5x+0.25x2=1+2x+x2
0.75x2+2.5x+0.75=0
divide the above equation by 2.5
0.3x2+x+0.3=0
Solving for x
a=0.3, b=1, c=0.3
x=2a−b±b2−4ac
x=2×0.3−1±1−4×0.3×0.3
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