Question

For the reaction a(g)+ b(g)=c(g)+d(g) occurring in a closed vessel of 1L volume the value of equilibrium constant is 16 at a particular temperature if the number of moles of each of the constituents be 1 then also calculate the molar concentration of b(g) and d(g)​

Answer 1

Answer:

ANSWER

     Option D is correct                      

                          A2+B2→C2+D2

At t=0                  1         1          1         1

t=eq                  1-x        1-x        1+x     1+x

KC=[1−x]2[1+x]2

Given KC=0.25   so

0.25=[1−x]2[1+x]2

0.25=1−2x+x21+2x+x2

0.25−0.5x+0.25x2=1+2x+x2

0.75x2+2.5x+0.75=0

divide the above equation by 2.5

0.3x2+x+0.3=0

Solving for x

a=0.3, b=1, c=0.3

x=2a−b±b2−4ac

x=2×0.3−1±1−4×0.3×0.3