Question

For the reaction (at 1240 k and 1 atm) caco3(s) cao(s) + co2(g)h = 176kj/mol; e will be

Answer 1

Since delta n means change in concentration ofproducts-change in concentration of reactants therefore delta n =1-0=1we must consider only gases only


H - nRT = E 176000 - 1 * 8.314 * 1240 = E 165690.64 J =E 165.6 J

Answer 2

Since delta n means change in concentration ofproducts-change in concentration of reactants therefore delta n =1-0=1we must consider only gases only

H - nRT = E 176000 - 1 * 8.314 * 1240 = E 165690.64 J =E 165.6 J