Question

For the reaction at 298K, 2A(s)+ B(g) → C(g) ∆U = -10.5 KJ and ∆S = -44.1JK-1 Calculate ∆G for the reaction and predict whether the reaction may occur spontaneously.​

Answer 1

Answer:

For the given reaction,  2 A(g) + B(g) → 2D(g)  ∆ng = 2 – (3)  = –1 mole  Substituting the value of ∆Uθ in the expression of ∆H:  ∆Hθ = ∆Uθ + ∆ngRT  = (–10.5 kJ) – (–1) (8.314 × 10–3 kJ K–1 mol–1 ) (298 K)  = –10.5 kJ – 2.48 kJ ∆Hθ = –12.98 kJ  Substituting the values of ∆Hθ and ∆Sθ in the expression of  ∆Gθ : ∆Gθ = ∆Hθ – T∆Sθ  = –12.98 kJ – (298 K) (–44.1 J K–1 )  = –12.98 kJ + 13.14 kJ  ∆Gθ = + 0.16 kJ  Since ∆Gθ for the reaction is positive, the reaction will not occur spontaneously. Read more on Sarthaks.com - https://www.sarthaks.com/8471/for-the-reaction-2a-g-b-g-2d-g-u-10-5-kj-and-s-44-1-jk-1

Explanation:

Answer 2

Answer:

For the reaction  2A(g) + B(g) → 2D(g)  ∆Uθ = –10.5 kJ and ∆Sθ = –44.1 JK–1 .  Calculate ∆Gθ for the reaction, and predict whether the reaction may occur spontaneously.Read more on Sarthaks.com - https://www.sarthaks.com/8471/for-the-reaction-2a-g-b-g-2d-g-u-10-5-kj-and-s-44-1-jk-1

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