for the reaction c2h4+h2= c2h2 ∆g°=240j at 47°c if 5 moles each of c2h4 and h2 are taken in 10 l vessel maintained at 47°c
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Answer:
H(C
2
H
4
)=H(C=C)+4×H(C−H)
=606.68+4×410.87=2250.16kJ/mol
Similarly,
H(H
2
)=431.79 kJ/mol
and
H(C
2
H
6
)=H(C−C)+6×H(C−H)=336.81+6×410.87=2802.03 kJ/mol
∴ H
(reaction)
=H(C
2
H
6
)−[H(H
2
)+H(C
2
H
4
)]
H
(reaction)
=2802.03−(431.79+2250.16)=120.08 kJ/mol.
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