Question

For the reaction caco3 -> cao + co2 kp=1 atm at 927 if 20 g of caco3 were kept in

Answer 1

Answer:

Since CaCO3 and CaO are solids, the value of Kp = partial pressure of CO2 = 1.16 atm.

Using ideal gas equation PV= nRT to calculate the number of moles of CO2 released.

n = PV/RT = 1.16 x 5.6) / 0.082 x 1073K

................= 0.0738 mol of CO2

From the equation, one mole of CaCO3 will form one mole of CO2

Hence, 0.0738 mol of CaCO3 has reacted.

Mass of CaCO3 reacted = 0.0738 x 100 g = 7.38 g

Terefore, percentage of CaCO3 reacted = 7.38/48 x 100%

.........................................................= 15.38%

Answer 2

Answer:

Since CaCO3 and CaO are solids, the value of Kp = partial pressure of CO2 = 1.16 atm.

Using ideal gas equation PV= nRT to calculate the number of moles of CO2 released.

n = PV/RT = 1.16 x 5.6) / 0.082 x 1073K

................= 0.0738 mol of CO2

From the equation, one mole of CaCO3 will form one mole of CO2

Hence, 0.0738 mol of CaCO3 has reacted.

Mass of CaCO3 reacted = 0.0738 x 100 g = 7.38 g

Terefore, percentage of CaCO3 reacted = 7.38/48 x 100%

.........................................................= 15.38%

Explanation: