Question

For the reaction co2(g)+h2g--------co(g)+h20(g) k is found to be 16 at a given temperature. originally equal number of moles of h2. and co2 were placed in the flask. at equilibrium the pressure of h2 is 1.20atm

Answer 1

Here's the answer..
Approve if understood

Answer 2

Hey dear,
I assume you want to calculate partial pressure of CO or H2O

◆ Answer-
P(CO) = P(H2O) = 4.8 atm

◆ Explaination-
# Given-
Kp = 16
P(H2) = x = 1.2 atm

# Solution-
Let's arrange the reaction better -
Reaction CO2 + H2 ---> CO + H2O
Initially p p 0 0
Equilibrium p-x p-x x x

Equilibrium constant is given by-
Kp = [H2O][CO] / [CO2][H2]
Kp = (p-x)(p-x) / x.x

We have value of Kp and x,
16 = (p-1.2)(p-1.2) / (1.2)(1.2)
p-1.2 = 1.2 × 4
p = 6 atm

Therefore,
P(CO) = 6-1.2 = 4.8 atm
P(H2O) = 6-1.2 = 4.8 atm

Hope this helps...